Categories:
.NET (357)
C (330)
C++ (183)
CSS (84)
DBA (2)
General (7)
HTML (4)
Java (574)
JavaScript (106)
JSP (66)
Oracle (114)
Perl (46)
Perl (1)
PHP (1)
PL/SQL (1)
RSS (51)
Software QA (13)
SQL Server (1)
Windows (1)
XHTML (173)
Other Resources:
Why does the call char scanf work?
Why does the call
char s[30];
scanf("%s", s);
work? I thought you always needed an & on each variable passed to scanf.
✍: Guest
You always need a pointer; you don't necessarily need an explicit &. When you pass an array to scanf, you do not need the &, because arrays are always passed to functions as pointers, whether you use & or not.
2015-10-30, 984👍, 0💬
Popular Posts:
From performance point of view how do they rate ? Repeater is fastest followed by Datalist and final...
What will be printed as the result of the operation below: main() { char s1[]="Cisco"; char s2[]="sy...
How can I execute a PHP script using command line? Just run the PHP CLI (Command Line Interface) pro...
How could Java classes direct program messages to the system console, but error messages, say to a f...
How do we create DCOM object in VB6? Using the CreateObject method you can create a DCOM object. You...