Why doesnt this code work?

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Why doesn't this code:
double d;
scanf("%f", &d);
work?

✍: Guest

Unlike printf, scanf uses %lf for values of type double, and %f for float.%f tells scanf to expect a pointer-to-float, not the pointer-to-double you gave it. Either use %lf, or declare the receiving variable as a float.

2015-10-30, 2184👍, 0💬

💬 2021-01-21 John Doe: Hello

How can I print numbers with commas separating the thousands? What about currency formatted numbers?
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Why doesnt this code work?
Why doesn't this code: double d; scanf("%f", &d); work? Unlike printf, scanf uses %lf for values of type double, and %f for float.%f tells scanf to expect a pointer-to-float, not the pointer-to-double you gave it. Either use %lf, or declare the receiving variable as a float. 2015-10-30, 2185👍, 0💬

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Why doesnt the call scanf work?
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Why does the call char scanf work?
Why does the call char s[30]; scanf("%s", s); work? I thought you always needed an & on each variable passed to scanf. You always need a pointer; you don't necessarily need an explicit &. When you pass an array to scanf, you do not need the &, because arrays are always passed to func... 2015-10-30, 2021👍, 0💬

What printf format should I use for a typedef like size_t when I don't know whether it is long or some other type?
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When I read numbers from the keyboard with scanf ...
When I read numbers from the keyboard with scanf and a "%d\n" format, like this: int n; scanf("%d\n", &n); printf("you typed %d\n", n); it seems to hang until I type one extra line of input. Perhaps surprisingly, \n in a scanf format string does not mean to expect a newline, but rather to re... 2015-10-23, 1787👍, 0💬

Why doesnt that code work?
Why doesn't the code short int s; scanf("%d", &s); work? When converting %d, scanf expects a pointer to an int. To convert to a short int, use %hd . 2015-10-28, 1730👍, 0💬

I am reading a number with scanf and d, and then a string with gets
I'm reading a number with scanf and %d, and then a string with gets(): int n; char str[80]; printf("enter a number: "); scanf("%d", &n); printf("enter a string: "); gets(str); printf("you typed %d and "%s"\n", n, str); but the compiler seems to be skipping the call to gets()! If, in response... 2015-10-23, 1713👍, 0💬

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