When I read numbers from the keyboard with scanf ...

Q

When I read numbers from the keyboard with scanf and a "%d\n" format, like this:
int n;
scanf("%d\n", &n);
printf("you typed %d\n", n);

it seems to hang until I type one extra line of input.

✍: Guest

A

Perhaps surprisingly, \n in a scanf format string does not mean to expect a newline, but rather to read and discard characters as long as each is a whitespace character. (In fact, any whitespace character in a scanf format string means to read and discard whitespace characters.Furthermore, formats like %d also discard leading whitespace, so you usually don't need explicit whitespace in scanf format strings at all.)
The \n in "%d\n" therefore causes scanf to read characters until it finds a non-whitespace character, and it may need to read another line before it can find that non-whitespace character. In this case, the fix is just to use "%d", without the \n (athough your program may then need to skip over the unread newline;scanf was designed for free-format input, which is seldom what you want when reading from the keyboard. By ``free format'' we mean that scanf does not treat newlines differently from other whitespace. The format "%d %d %d" would be equally happy reading the input
1 2 3

or
1
2
3

(By way of comparison, source code in languages like C, Pascal, and LISP is free-format, while traditional BASIC and FORTRAN are not.)
If you're insistent, scanf can be told to match a newline, using the ``scanset'' directive:
scanf("%d%*[\n]", &n);
Scansets, though powerful, won't solve all scanf problems,

2015-10-23, 684👍, 0💬