Categories:
.NET (357)
C (330)
C++ (183)
CSS (84)
DBA (2)
General (7)
HTML (4)
Java (574)
JavaScript (106)
JSP (66)
Oracle (114)
Perl (46)
Perl (1)
PHP (1)
PL/SQL (1)
RSS (51)
Software QA (13)
SQL Server (1)
Windows (1)
XHTML (173)
Other Resources:
Why doesnt the call scanf work?
Why doesn't the call scanf("%d", i) work?
✍: Guest
The arguments you pass to scanf must always be pointers: for each value converted, scanf ``returns'' it by filling in one of the locations you've passed pointers to. To fix the fragment above, change it to scanf("%d", &i) .
2015-11-02, 1816👍, 0💬
Related Topics:
Popular Posts:
What is the version information in XML? “version” tag shows which version of XML is used.
How To Compare Two Strings with strcmp()? - PHP Script Tips - PHP Built-in Functions for Strings PHP...
How To List All Values of Submitted Fields? - PHP Script Tips - Processing Web Forms If you want lis...
How do we generate strong names ? or What is use the of SN.EXE ? or How do we apply strong names to ...
How does one iterate through items and records in a specified block? One can use NEXT_FIELD to itera...
