How can I dynamically allocate arrays?

Q

How can I dynamically allocate arrays?

✍: Guest

A

The equivalence between arrays and pointers allows a pointer to malloc'ed memory to simulate an array quite effectively. After executing
#include <stdlib.h>
int *dynarray;
dynarray = malloc(10 * sizeof(int));

(and if the call to malloc succeeds), you can reference dynarray[i] (for i from 0 to 9) almost as if dynarray were a conventional, statically-allocated array (int a[10]). The only difference is that sizeof will not give the size of the ``array''

2016-04-23, 619👍, 0💬